## Force Formula

TGIF, Friends Worldwide from Dr. TJ Gunn in Houston Texas USA……

Force is the mass of an object, multiplied by its acceleration. The unit of force is . This is called a Newton, with the symbol N. Force has a magnitude and a direction.

force = mass x acceleration

F = ma

F = force

m = mass

a = acceleration

Force Formula Questions:

1) A 0.15 kg coconut falls out of its tree. The acceleration due to gravity is 9.80 m/s2, down. What is the force acting on the coconut due to gravity?

Answer: The force can be found using the equation:

F = ma

F = (0.15 kg)(9.80 m/s2)

F = 1.47

F = 1.47 N

The force due to gravity acting on the coconut is 1.47 N, down.

2) A man pushes a 50.0 kg block of ice across a frozen pond. He applies a force of 25.0 N, pushing the block away from him. What is the acceleration of the block?

Answer: To find the acceleration, rearrange the equation:

The block is accelerating 0.50 m/s2, directed away from the man.

## Acceleration Formula

TGIF, friends Worldwide from Dr. TJ Gunn in Houston Texas, USA……

Acceleration is a measure of how quickly the velocity of an object changes. So, the acceleration is the change in the velocity, divided by the time. Acceleration has a magnitude (a value) and a direction. The direction of the acceleration does not have to be the same as the direction of the velocity. The units for acceleration are meters per second squared (m/s2).

a = acceleration (m/s2)

vf = the final velocity (m/s)

vi = the initial velocity (m/s)

t = the time in which the change occurs (s)

Δv = short form for “the change in” velocity (m/s)Acceleration Formula Questions:

1) A sports car is travelling at a constant velocity v = 5.00 m/s. The driver steps on the gas, and the car accelerates forward. After 10.0 seconds, the driver stops accelerating and maintains a constant velocity v = 25.0 m/s. What was the car’s acceleration?

Answer: The initial velocity is vi = 5.00 m/s, in the forward direction. The final velocity is vf = 25.0 m/s in the forward direction. The time in which this change occurred is 10.0 s. The acceleration is in the forward direction, with a value:

The car’s acceleration is 2.00 m/s2, forward.

2) A child drops a rock off of a cliff. The rock falls for 15.0 s before hitting the ground. The acceleration due to gravity is g = 9.80 m/s2. What was the velocity of the rock the instant before it hit the ground?

Answer: The rock was released from rest, so the initial velocity is vi = 0.00 m/s. The time in which the change occurred is 15.0 s. The acceleration is 9.80 m/s2. The final velocity must be found, so rearrange the equation:

vf = vi + at

vf = 0.00 m/s +(9.80 m/s2)(15.0 s)

vf = 147 m/s

The rock is falling, so the direction of the velocity is down.